笛卡儿坐标下的螺旋线
x = 4 * cos ( t *(5*360))
y = 4 * sin ( t *(5*360))
z = 10*t作者: X_Design 时间: 2004-3-10 12:48
beginner007 wrote:
圆柱坐标(cylindrical)螺旋线(Helical curve)
r=t
theta=10+t*(20*360)
z=t*3
笛卡儿坐标下的螺旋线
x = 4 * cos ( t *(5*360))
y = 4 * sin ( t *(5*360))
z = 10*t