【讨论】Simens 840D 后处理圆弧 （加分）

有人提出做这样的程序格式
N10 FFWON
N11 SOFT
N12 CFIN
N13 OFFN = 0
N14 G90 G54 G642
N15 T1 D1
N16 M06
COMPCAD
N17 S4000 M3
N18 G0 X6. Y-89.95
N19 Z100. M8
N20 Z47.4
N21 G1 Z44.4 F1750
N22 Y-89.65 F2500
N23 G3 X0. Y-83.65 I=AC(0.) J=AC(-89.65)
N24 G1 X-102.
N25 G2 X-141.65 Y-44. I=AC(-102.) J=AC(-44.)
N26 G1 Y44.
N27 G2 X-102. Y83.65 I=AC(-102.) J=AC(44.)
N28 G1 X102.
N29 G2 X141.65 Y44. I=AC(102.) J=AC(44.)
N30 G1 Y-44.
N31 G2 X102. Y-83.65 I=AC(102.) J=AC(-44.)
N32 G1 X0.
N33 G3 X-6. Y-89.65 I=AC(0.) J=AC(-89.65)
N34 G1 Y-89.95
N35 G0
N36 Z45.4
N37 X6.
N38 G1 Z42.4 F1750
N39 Y-89.65 F2500
N40 G3 X0. Y-83.65 I=AC(0.) J=AC(-89.65)
N41 G1 X-102.
N42 G2 X-141.65 Y-44. I=AC(-102.) J=AC(-44.)
N43 G1 Y44.
N44 G2 X-102. Y83.65 I=AC(-102.) J=AC(44.)
  
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N115148 G1 Y-68.15
N115149 G0
N115150 Z100. M9
N115151 T4 D1
N115152 M06
N115153 S1500 M3
N115154 G0 X6. Y-73.15
N115155 Z100. M8
N115156 Z1.3
N115157 G1 Z.3 F150
N115158 Y-72.85 F500
N115159 G3 X0. Y-66.85 I=AC(0.) J=AC(-72.85)
N115160 G1 X-102.
N115161 G2 X-124.85 Y-44. I=AC(-102.) J=AC(-44.)
N115162 G1 Y44.
N115163 G2 X-102. Y66.85 I=AC(-102.) J=AC(44.)
N115164 G1 X102.
N115165 G2 X124.85 Y44. I=AC(102.) J=AC(44.)
N115166 G1 Y-44.
N115167 G2 X102. Y-66.85 I=AC(102.) J=AC(-44.)
N115168 G1 X0.
N115169 G3 X-6. Y-72.85 I=AC(0.) J=AC(-72.85)
N115170 G1 Y-73.15
N115171 G0
N115172 Z100. M9
N115173 M09
N115174 M05
N115175 FFWOF
N115176 M30
  
俺已做好，请各位有兴趣的试试~~
  
有问题可以提出

俺试做了一下
  
N100 FFWON
N101 SOFT
  
N102 CFIN
  
N103 OFFN = 0
N104 G90 G53 G642
N105 T01 D1
N106 M06
COMPCAD
  
N107 S1500 M03
N108 G00 X-38.568 Y7.539
N109 Z25. M08
N110 Z8.
N111 Z5.
N112 G03 X-45.478 Y6.947 I=AC ( 2.936 ) J=AC ( 6.354 ) F1200.
N113 G03 X-47.495 Y5.471 I=AC ( -25.478 ) J=AC ( 36.947 )  
N114 G03 X-47.495 Y5.471 I=AC ( -27.495 ) J=AC ( 35.471 )
N115 G03 X-49.427 Y3.886 I=AC ( -27.495 ) J=AC ( 35.471 )  
N116 G03 X-51.798 Y-2.146 I=AC ( -4.589 ) J=AC ( 5.286 )  
N117 G00 Z25.
N118 M09
N119 M05
N120 FFWON
N121 M30

文件

放假了

能不能在XZ，YZ面走出圆弧来啊

X-6.827 Z-.486
X-6.274 Z-.372
X-6.16 Z-.349
X-5.831 Z-.306
X-5.733 Z-.291
X-5.188 Z-.239
X-5.032 Z-.229
X-4.829 Z-.222
  
这段程式能不能在一用一个圆弧走出来

G02XYIJ
  
XY此时是终点坐标,IJ是以起点建立坐标系,圆弧的圆心相对与该坐标系的XY的值
  
G02XYI=AC()J=AC()
  
XY此时是终点坐标,IJ的值应该指的是圆心相对于坐标系的XY的值
  
另外还有AR,CP等多种格式,常用的是上面两种

试作了一个，请各位前辈PP。

这是图形，还有上面两位前辈的怎么是G53，它我记得是机械座标啊，我G代码不熟。

ycyddh wrote:
能不能在XZ，YZ面走出圆弧来啊

當然可以!!!
1.Machine Control需要注意一下!!