【题目】超弹非线形分析(1到2分）

一轴对称橡胶堆，边界条件如图，分析反力－位移曲线!
V＝0.499
E＝2e5
单轴压缩数据
应变：-0.45,-0.4,-0.35,-0.3,-0.25,-0.2,-0.15,-0.1,-0.05
应力：-256,-128,-64,-32,-16,-8,-4,-2,-1
  
单轴拉伸数据
应变：0.0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9
应力：0.0,1,1.5,2.0,2.9,3.6,5,7.5,9.7,17
  
体积试验数据
1 0  
0.99 20

命令流我不会啊，但粗看了一下，好像没有做接触啊，

Dear CAE Master,
  I draw the model on Solidworks and output ACIS format, however,
I still can not solve it since I only can get the compression value on -0.03 meter(not -50 mm). The code is listed below. I would appreciate that you can help me to check and solve it. Thanks!!
  
ET,1,PLANE183   !* element 183
!*   
!*   
MPTEMP,,,,,,,,   
MPTEMP,1,0   
MPDATA,EX,1,,2e5
MPDATA,PRXY,1,,0.499
*CREATE,file1.UNIA       !* <-- input compression and tension data
  -0.45 -256  
  -0.4 -128   
  -0.35 -64   
  -0.3 -32   
  -0.25 -16   
  -0.2 -8
  -0.15 -4   
  -0.1 -2
  -0.05 -1   
  0 0
  0.1 1   
  0.2 1.5
  0.3 2.0
  0.4 2.9
  0.5 3.6
  0.6 5   
  0.7 4.5
  0.8 9.7
  0.9 17  
*END
TBFT,EADD,1,UNIA,file1.UNIA  
/DELETE,file1.UNIA   
*CREATE,file1.VOLU   
  1 0
  0.99 20
*END
TBFT,EADD,1,VOLU,file1.VOLU  
/DELETE,file1.VOLU   
TBFT,FADD,1,HYPER,MOON,9
TBFT,SOLVE,1,HYPER,MOON,9,1  
TBFT,FSET,1,HYPER,MOON,9
~SATIN,Surface,SAT,'..\',SOLIDS,0   
/NOPR   
/GO  
FINISH   
/PREP7   
SMRT,3   
MSHAPE,0,2D  
MSHKEY,0
!*   
CM,_Y,AREA   
ASEL, , , ,       1  
CM,_Y1,AREA  
CHKMSH,'AREA'   
CMSEL,S,_Y   
!*   
AMESH,_Y1   
!*   
CMDELE,_Y   
CMDELE,_Y1   
CMDELE,_Y2   
!*   
FINISH   
/SOL
ANTYPE,0
ANTYPE,0
NLGEOM,1
CUTCONTROL,NOITERPRED,1  
FLST,2,1,4,ORDE,1   
FITEM,2,3   
!*   
/GO  
DL,P51X, ,UY,0              !*<- boundary constraint on bottom line
DL,       2, ,SYMM           !*<- boundary constraint on left line symm
FLST,2,1,4,ORDE,1   
FITEM,2,1   
!*   
/GO  
DL,P51X, ,UY,-0.05  !*<- boundary constraint on top line by moving down 50  
/STATUS,SOLU
/STATUS,SOLU
SOLVE

1wjlin wrote:
Thanks!! I have seen it but I still get some of question as listed below,  
  
  1. ....体积试验数据有所不同，每一行两个数据同样用空格隔开，第二个数为静水压力，但第一个数不是体积应变e，而是相对体积，即1+e (<--- ???)，例如体积应变为-0.01，则应该在第一列输入0.99。而且程序假定体积试验为线性关系，拟合时也只拟合出一条直线，所以通常输入两个值即可。数据符号：使体积减小的静水压力为正，这需要注意，如下例：   
  0 0       <------ Error? or should be  1 0  
  0.99 20   
  
  2. ...mooney还有其他一些推导基于几乎不可压缩，所以对mooney模型而言，输入参数时一定要注意其泊松比应该接近0.5，一般大于0.49。 <---- Error?? Your proxy V=-0.499  
  
  I am sorry about these questions but I also want to solve your question for personal interesting!! I hope that you don't mind it.

  
Sorry!  
有两个错误：
泊松比=0.499
关于超弹新功能介绍原文有误：
例子应该为：
1 0
0。99 20
谢谢你的细心！

Thanks!! I have seen it but I still get some of question as listed below,
  
1. ....体积试验数据有所不同，每一行两个数据同样用空格隔开，第二个数为静水压力，但第一个数不是体积应变e，而是相对体积，即1+e (<--- ???)，例如体积应变为-0.01，则应该在第一列输入0.99。而且程序假定体积试验为线性关系，拟合时也只拟合出一条直线，所以通常输入两个值即可。数据符号：使体积减小的静水压力为正，这需要注意，如下例：  
0 0       <------ Error? or should be  1 0
0.99 20  
  
2. ...mooney还有其他一些推导基于几乎不可压缩，所以对mooney模型而言，输入参数时一定要注意其泊松比应该接近0.5，一般大于0.49。 <---- Error?? Your proxy V=-0.499
  
I am sorry about these questions but I also want to solve your question for personal interesting!! I hope that you don't mind it.

1wjlin wrote:
Do you mind to explain the V symbol and Volumetric experiment data?  
  Thanks!!

https://www.icax.org/viewthread. ... %3D1&page=#pid=&age=60[/url]

Do you mind to explain the V symbol and Volumetric experiment data?
Thanks!!